Предмет: Алгебра, автор: ilgizanarmmatov07

36y⁸-1

скажите пожалуйста​

Ответы

Автор ответа: NNNLLL54
2

Ответ.

36y^8-1=(6y^4)^2-1^2=(6y^4-1)(6y^4+1)=\\\\=(\sqrt6y^2-1)(\sqrt6y^2+1)(6y^4+1)=\\\\=(\sqrt[4]6y-1)(\sqrt[4]6y+1)(\sqrt6y^2+1)(6y^4+1)

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