Предмет: Геометрия, автор: ikha241006

Найти площадь треугольника если его периметр равен 64 см высота проводится к основанию 8 см а стороны относится как 3:6:7

Ответы

Автор ответа: ason2121

5Х ШИРИНА
7Х ДЛИНА
(5Х+7Х)*2=144
12Х=144 :2
12Х=72
Х=6 СМ 1 ЧАСТЬ
5*6=30 СМ ШИРИНА ПРЯМОУГОЛЬНИКА
7*6=42 СМ ДЛИНА ПРЯМОУГОЛЬНИКА
S=30*42=1260 КВ.СМ ПЛОЩАДЬ ПРЯМОУГОЛЬНИКА

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