Предмет: Алгебра, автор: dasademncuk

диагональ прямокутника доривнюе 20 см, 1 из сторин 16см. Опчислити плошу прямокутника​

Ответы

Автор ответа: Sanya2263
2

АВ=CD=16 см, АС=BD=20 см.

По теореме Пифагора:

ВС²=АС²-АВ²

ВС = √(АС²-АВ²) = √(20²-16²) = √144 = 12(см)

S=AB*BC=16*12=192(см²)

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