Question

помогите пожалуйста, даю 30 баллов

Answer 1

Ответ:

$1)\ \ \left\{\begin{array}{l}x^2-4\leq 0\\3x-2<0\end{array}\right\ \ \left\{\begin{array}{l}(x-2)(x+2)\leq 0\\x<\dfrac{2}{3}\end{array}\right\ \ \left\{\begin{array}{l}x\in [-2\ ;\ 2\ ]\\x\in (-\infty ;\frac{2}{3}\, )\end{array}\right\\\\\\x\in \Big[-2\, ;\, \dfrac{2}{3}\ \Big)$

$2)\ \ \left\{\begin{array}{l}x^2-9\leq 0\\2x-5<0\end{array}\right\ \ \left\{\begin{array}{l}(x-3)(x+3)\leq 0\\x<2,5\end{array}\right\ \ \left\{\begin{array}{l}x\in [-3\ ;\ 3\ ]\\x\in (-\infty ;\ 2,5\ )\end{array}\right\\\\\\x\in [\, -3\ ;\ 2,5\ )$

$3)\ \ \left\{\begin{array}{l}x^2-9>0\\3x-2\geq 0\end{array}\right\ \ \left\{\begin{array}{l}(x-3)(x+3)>0\\x\geq \dfrac{2}{3}\end{array}\right\ \ \left\{\begin{array}{l}x\in (-\infty ;-3)\cup (\, 3\, ;+\infty\, )\\x\in [\ \frac{2}{3}\, ;+\infty \, )\end{array}\right\\\\\\x\in (\ 3\ ;+\infty \, )$