Предмет: Алгебра, автор: Alinaaaaaaaaaaaaa0

розв'яжіть рівняння помогите​

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Автор ответа: Universalka
1

\frac{x^{2}-6 }{x-3}=\frac{x}{x-3} \\\\\frac{x^{2}-6 }{x-3}-\frac{x}{x-3} =0\\\\\frac{x^{2}-x-6 }{x-3}=0\\\\\frac{(x-3)(x+2)}{x-3}=0\\\\x-3\neq 0 \ \Rightarrow \ x\neq3\\x+2=0 \ \Rightarrow \ x=-2\\\\Otvet:\boxed{-2}

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