Question

Помогите решить:
log4log16 256+log 4 √2​

Answer 1

Ответ:

$log_{ 4 }( log_{16}(256) ) + log_{4}( \sqrt{2} ) = log_{4}(2) + log_{4}( \sqrt{2} ) = \\ = log_{4}(2 \sqrt{2} ) = log_{ {2}^{2} }( {2}^{ \frac{3}{2} } ) = \frac{1}{2} \times \frac{3}{2} log_{2}(2) = \frac{3}{4} = 0.75$