Question

Срочно Найти производную функции:

1. Y= 3x - 9cos x;
2. Y=9x5 + 2sinx - 10;
4. Y = 2.x tgx;

Answer 1

Ответ:

1

$y = 3x - 9 \cos(x)$

$y '= 3 - ( - 9 \sin(x)) = 3 + 9 \sin(x)$

2

$y = 9 {x}^{5} + 2 \sin(x) - 10$

$y '= 9 \times 5 {x}^{4} + 2 \cos(x) - 0 = \\ = 45 {x}^{4} + 2 \cos(x)$

3

$y = 2xtgx$

$y '= (2x)'tgx + (tgx) '\times 2x = \\ = 2tgx + \frac{2x}{ \cos {}^{2} (x) }$