Question

2х^-7х+6<0 памагите..............​

Answer 1

Ответ:

$2 {x}^{2} - 7x + 6 < 0 \\ d = ( - 7) {}^{2} - 4 \times 2 \times 6 = 1 \\ x1 = \frac{7 + 1}{4} = 2 \\ x2 = \frac{7 - 1}{4} = \frac{3}{2}$

Ответ:

$( \frac{3}{2} \: \: 2)$