Question

(x²-9)²-4(x²-9)+3=0 помогите решить

Answer 1

Ответ:

(x²-9)²-4(x²-9)+3=0

${t}^{2} - 4t + 3 = 0 \\ t = 1 \\ t = 3$

${x}^{2} - 9 = 1 \\ {x}^{2} - 9 = 3$

${x} = - \sqrt{10 } \\ x = \sqrt{10} \\ x = - 2 \sqrt{3} \\ x = 2 \sqrt{3}$

ОТВЕТ:

$x1 = - 2 \sqrt{3} \\ x2 = - \sqrt{10} \\ x3 = \sqrt{10} \\ x4 = 2 \sqrt{3}$