Question

6.57. Докажите тождество

Answer 1

Ответ:

$\frac{1}{( a- b)(b -c )} + \frac{1}{(c -a )(a - b)} + \frac{1}{( b- c)(c - a)} = \\ = \frac{(c - a) + (b - c) + ( a - b)}{(a - b)(b - c)(c - a)} = \frac{c - a + b - c + a - b}{(a - b)(b - c)(c - a)} = \\ = \frac{0}{(a - b)(b - c)(c - a)} = 0$

Answer 2

Ответ:

$\frac{c - a + b - c + a - b}{(a - b)(b - c)(c - a)} = 0$

$0 = 0$