Question

Разложить на множители
а)16а^4-1
б)у^2-х^2-4х-4

Answer 1

а)

$16a { }^{4} - 1 = (4a {}^{2} - 1) \times (4a {}^{2} + 1) =(2a - 1) \times (2a + 1) \times (4a {}^{2} + 1)$

б)

$y {}^{2} - x {}^{2} - 4x - 4 = y {}^{2} - (x {}^{2} + 4x + 4) = y {}^{2} - (x + 2) {}^{2} = (y - (x + 2)) \times (y + (x + 2)) = (y - x - 2) \times (y + x + 2)$