Предмет: Алгебра, автор: zamanovasonya74

40.6 найдите значение выражения

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Автор ответа: Universalka

15

$\frac{(x-2)^{2} }{4y+9}*\frac{2y+6}{x^{2}-4 }=\frac{(x-2)^{2}*2(y+3) }{(4y+9)*(x-2)(x+2)}=\frac{(x-2)*2(y+3)}{(4y+9)*(x+2)}\\\\x=0,5 \ ; \ y=-1,5\\\\\frac{(x-2)*2(y+3)}{(4y+9)*(x+2)}=\frac{(0,5-2)*2(-1,5+3)}{(4*(-1,5)+9)(0,5+2)}=\frac{-1,5*2*1,5}{(-6+9)*2,5}=-\frac{3*1,5}{3*2,5}=\boxed{-0,6}$

Аноним: Добрый вечер. Не могли бы Вы помочь мне с одним неравенством ? Вопрос в профиле, заранее спасибо

hyfdedr: вы расписывайте как делаете

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