Question

Терміново! Даю 20 балів​

Answer 1

Ответ:

Вот........

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Answer 2

Ответ:

$4x^{2} - 7x - 2 = 0 \\ d = \sqrt{49 + 4 \times 4 \times 2} = 9 \\ x = \frac{7 \binom{ + }{ - }9}{2} = 8 | - 1$

$11x - 4x ^{2} + 3 = 0 \\ 4x^{2} - 11x - 3 = 0 \\ d = \sqrt{121 + 4 \times 4 \times 3} = 13 \\ x = \frac{11 \binom{ + }{ - }13 }{2} = 12 | - 1$

$\frac{4 \times ( - 1)^{2} - 7 \times ( - 1) - 2 }{11 \times ( - 1) - 4 \times ( - 1) ^{2} + 3 } = \frac{4 + 7 - 2}{ - 11 - 4 + 3} = \frac{9}{ - 12} = - \frac{3}{4}$