Question

помогите решить..........​

Answer 1

Ответ:

1)

  $(5x^{12} -3x^{-4}- \frac{2}{x^{7} } +2)' = 5*12x^{11} -3*(-4x^{-5} )-(2*\frac{7x^{6} }{(x^{7})^{2} } )+0 = 60x^{11} +12x^{-5} -(2*\frac{7x^{6} }{x^{14} } ) = 60x^{11} +12x^{-5} -(2*\frac{7 }{x^{8} } ) = 60x^{11} +12x^{-5} +\frac{14 }{x^{8} } = 60x^{11} +\frac{12}{x^{5} } +\frac{14 }{x^{8} } = \frac{60x^{19}+12x^{3}+14 }{x^{8} }$

2)

  $(\frac{1}{3} x^{3} -\frac{4}{5} x^{5} +\frac{12}{6} x^{6} -\frac{1}{18} x^{9} )' =\frac{1}{3} *3x^{2} -\frac{4}{5} *5x^{4} + \frac{12}{6} *6x^{5} -\frac{1}{18}*9x^{8} =x^{2} -4x^{4} + 2 *6x^{5} -\frac{1}{2} x^{8} = x^{2} -4x^{4} +12x^{5} -\frac{1}{2} x^{8}$

3)

  $((30x^{2} -2)*(5x^{3} +2x^{2} ))' = (150x^{5}+60x^{4}-10x^{3}-4x^{2})'= 150*5x^{4}+60*4x^{3} -10*3x^{2} -4*2x = 750x^{4} 240x^{3} -30x^{2} -8x$