Question

упростите выражение (cos(a-b)-cosacosb) /(cos(a+b) +sinasinb)

Answer 1

1) sin(a+B)-cos(a-B) = sinacosB+ cosasinB - cosacosB - sinasinB =

(sinacosB- sinasinB )+ (cosasinB - cosacosB) = sina(cosB -sinB) +cosa(sinB - cosB) =

= sina(cosB -sinB) - cosa(cosB- sinB ) = (cosB -sinB) ( sina - cosa)

2) cos(a+B)-sin(a-B) = cosacosB - sinasinB- sinacosB+ cosasinB =

= (cosacosB + cosasinB) - (sinasinB + sinacosB) = cosa(cosB + sinB) - sina(sinB + cosB) =

= (cosB + sinB)( cosa -sina)

3) (cosB -sinB) ( sina - cosa)/ (cosB + sinB)( cosa -sina) = (sinB -cosB)/ ( sinB+ cosB )

Вот, вроде правильно