Предмет: Математика, автор: alex2687

6. Прямой угол АСВ лучом CD разбили на два угла. Найдите градусные меры углов, если известно, что
угол ACD на 30° больше угла BCD.

Ответы

Автор ответа: vde130890
0

Ответ:

Пошаговое объяснение:

Угол АСD = 60°

Угол BCD = 30°

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