Question

1) x⁴ -18x² +32 =0
2) (x²+x) +6=0​

Answer 1

x^4-18x^2+32=0

По т. Виета: x1*x2=32 x1+x2=18 =>

x^2=16 => x=4 x=-4

x^2=2 => $x=\sqrt{2}$ $x=-\sqrt{2}$

Ответ: -4 ; $-\sqrt{2}$ ; $\sqrt{2}$ ; 4.

x^2+x+6=0

D=1^2-4*6*1<0 => решений нет.