Question

розв'язати рівняння методом заміни (x+3)^2-3(x+3)-4=0

Answer 1

${(x + 3)}^{2} - 3(x + 3) - 4 = 0 \\ {(x + 3)}^{2} + (x + 3) - 4(x + 3) - 4 = 0 \\ (x + 3) \times (x + 3 + 1) - 4(x + 3 + 1) = 0 \\ (x + 3 + 1) \times (x + 3 - 4) = 0 \\ (x + 4) \times (x - 1) = 0 \\ x + 4 = 0 \\ x - 1 = 0 \\ x = - 4 \\ x = 1 \\ {x}^{1} = - 4, {x}^{2} = 1$