Question

Помогите с решением пожалуйста, срочно! Даю 50 баллов

Answer 1

Ответ:

11

$log_{ \frac{1}{13} }( \sqrt{13} ) = log_{ {13}^{ - 1} }( {13}^{ \frac{1}{2} } ) = - 1 \times \frac{1}{2} = - 0.5$

12

$6 \times log_{7}( \sqrt[3]{7} ) = -6 \times log_{7}( {7}^{ \frac{1}{3} } ) = 6 \times \frac{1}{3} = 2$

13

$log {}^{2} _{ \sqrt{7} }(49) = log {}^{2} _{ \sqrt{7} }(( \sqrt{7} ) {}^{4} ) = {4}^{2} = 16$

14

$7 \times {5}^{ log_{5}(4) } = 7 \times 4 = 28$

15

$\frac{24}{ {3}^{ log_{3}(2) } } = \frac{24}{2} = 12$

16

${5}^{3 + log_{5}(2) } = {5}^{3} \times {5}^{ log_{5}(2) } = 125 \times 2 = 250$

17

${8}^{2 log_{8}(3) } = {8}^{ log_{8}( {3}^{2} ) } = {8}^{ log_{8}(9) } = 9$

18

${36}^{ log_{6}(2) } = {6}^{2 log_{6}(2) } = {6}^{ log_{6}( {2}^{2} ) } = 4$

19

${64}^{ log_{8}( \sqrt{3} ) } = {8}^{2 log_{8}( \sqrt{3} ) } = {8}^{ log_{8}(( \sqrt{3}) {}^{2} ) } = 3$

20

${5}^{ log_{25}(49) } = {5}^{ log_{ {5}^{2} }(49) } = {5}^{ \frac{1}{2} log_{5}(49) } = \\ = {5}^{ log_{5}( {49}^{ \frac{1}{2} } ) } = 7$

21

$( {3}^{ log_{2}(3) } ) {}^{ log_{3}(2) } = {3}^{ log_{2}(3) \times log_{3}(2) } = {3}^{1} = 3$