Question

Знайдіть похідну функції: f(x)=(6х+3)(х²-10)

Answer 1

Ответ:

$f(x) = (6x + 3)( {x}^{2} - 10)$

$f'(x) = (6x + 3)'( {x}^{2} - 10) + ( {x}^{2} - 10)'(6x + 3) = \\ = 6( {x}^{2} - 10) + 2x(6x + 3) = 6 {x}^{2} - 60 + 12{x}^{2} + 6x = \\ = 18 {x}^{2} + 6x - 60$