Question

Помогите найти производную

Answer 1

Ответ:

$y = 4 {x}^{3} - \frac{2}{ {x}^{2} } + 15 \sqrt[5]{ {x}^{4} } + 15$

$y' = (4 {x}^{3} - 2 {x}^{ - 2} + 15 {x}^{ \frac{4}{5} } + 15) = \\ = 12 {x}^{2} - 2 \times ( - 2) {x}^{ - 3} + 15 \times \frac{4}{5} {x}^{ - \frac{1}{5} } + 0 = \\ = 12 {x}^{2} + \frac{4}{ {x}^{3} } + \frac{12}{ \sqrt[5]{x {}^{1} } } + 0$