Question

2+2x²-3x=0
допоможіть будь ласка ​

Answer 1

$2+2x^{2}-3x=0$

$2x^{2}+2=3x$

$x(2x-3)+2=0$

$\frac {16}{7}(x-\frac {3}{4})^{2}=-1$

$x_{1}=\frac {1}{4}(3-i\sqrt{7})$

$x_{2}=\frac {1}{4}(3+i\sqrt{7})$