Question

сократить дробь:а-6√а+9/√а-3​

Answer 1

$\frac{a-6\sqrt{a}+9 }{\sqrt{a}-3 }=\frac{(\sqrt{a})^{2}-2*\sqrt{a} *3+3^{2}}{\sqrt{a}-3 }=\frac{(\sqrt{a}-3)^{2}}{\sqrt{a}-3 }=\boxed{\sqrt{a}-3}$