Question

решите неравенства даю 30 баллов​

Answer 1

Ответ:

$1)\ \ x(x-4)(x-4,2)(x-4\frac{1}{3})<0\\\\znaki:\ \ \ +++(0)---(4)+++(4,2)---(4\frac{1}{3})+++\\\\x\in (\ 0\ ;\ 4\ )\cup (\, 4,2\ ;\ 4\frac{1}{3}\, )\\\\\\2)\ \ x(7x+2)(3-x)(x^2+4)>0\ \ \to \ \ x(7x+2)(x-3)(x^2+4)<0\\\\znaki:\ \ ---(-\frac{2}{7})+++(0)---(3)+++\\\\x\in (-\infty ;-\frac{2}{7}\, )\cup (\ 0\ ;\ 3\ )$

$3)\ \ (x-8)(2x-15)(x-6)^2<0\\\\znaki:\ \ +++(6)+++(7,5)---(8)+++\\\\x\in (\, 7,5\ ;\ 8\ )\\\\\\4)\ \ x^2(x+1)(x-3)^2>0\\\\znaki:\ \ ---(-1)+++(0)+++(3)+++\\\\x\in (-1\ ;\ 0)\cup (\ 0\ ;\ 3)\cup (\ 3\ ;+\infty \, )\\\\\\5)\ \ (x^2+x)(49-x^2)<0\ \ \to \ \ \ \ x(x+1)(7-x)(7+x)<0\ \ ,\\\\x(x+1)(x-7)(x+7)>0\\\\znaki:\ \ +++(-7)---(-1)+++(0)---(7)+++\\\\x\in (-\infty \, ;-7\, )\cup (-1\ ;\ 0\ )\cup (\ 7\, ;+\infty \, )$