Question

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Answer 1

$5Sinx Cosx+14Cos^{2}x=0\\\\Cosx(5Sinx+14Cosx)=0\\\\\left[\begin{array}{ccc}Cosx=0\\5Sinx+14Cosx=0|:Sinx\neq0 \end{array}\right\\\\\\\left[\begin{array}{ccc}x=\frac{\pi }{2}+\pi n,n\in Z \\5+14Ctgx=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x=\frac{\pi }{2}+\pi n,n\in Z \\x=-arcCtg\frac{5}{14}+\pi n,n\in Z \end{array}\right$