Question

ПОМОГИТЕ ПЖЖЖЖЖ СРОЧНО 15 БАЛЛОВ ДАЮ​

Answer 1

Ответ:1 3y

Пошаговое объяснение:

Answer 2

Ответ:

a)$\frac{5y-2}{y+1}-2=\frac{3y-4}{y^{2}-1 }$

y≠-1; y≠1

$\frac{(y-1)(5y-2)-2(y-1)(y+1)-(3y-4)}{(y-1)(y+1)} =0$

$\frac{5y^{2}- 2y-5y+2-2y^{2} +2-3y+4 }{(y-1)(y+1)}=0$

$\frac{3y^{2}-10y+8 }{(y-1)(y+1)}=0$

3y²-10y+8=0

y(3y-4)-y(3y-4)=0

(3y-4)(y-2)=0

3y-4=0

y-2=0

y=4/3

y=2

б)$\frac{2y+5}{y-3}-\frac{y+18}{y^{2}-9 }=3$

y≠3; y≠-3

$\frac{2y+5}{y-3}-\frac{y+18}{(y-3)(y+3)} -3=0$

$\frac{2y^{2}+5y+6y+15-y-18-3y^{2}+27 }{(y-3)(y+3)}=0$

$\frac{-y^{2}+10y+24 }{(y-3)(y+3)} =0$

y²-10y-24=0

y(y+2)-12(y+2)=0

(y+2)(y-12)=0

y+2=0

y-12=0

y=-2

y=12

Пошаговое объяснение: