Question

помогите даю 50 баллов​

Answer 1

Відповідь:

$\frac{2}{y^2-yx} -\frac{2}{yx-x^2} =\\\\\frac{2}{y(y-x)} -\frac{2}{x(y-x)} =\\\\\frac{2x}{y(y-x)} -\frac{2y}{x(y-x)} =\\\\\frac{2x-2y}{xy(y-x)}=\\\\- \frac{2(x-y)}{xy(x-y)}=\\\\-\frac{2}{xy}$

x=2

y=-3

$-\frac{2}{xy}=-\frac{2}{2*(-3)}=\frac{2}{6}=\frac{1}{3}$

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