Question

за весь листок лам 45 баллов​

Answer 1

Ответ:

$1)(x - y)(x + y) = {x}^{2} - {y}^{2} \\ 2)(2a - 3b)(2a + 3b) = {4a}^{2} - {9b}^{2} \\ 3)(8b - 5a)(8b + 5a) = {64b}^{2} - {25a}^{2}$

$4)(2c - 10)(2c + 10) = {4c}^{2} - 100 \\ 5)(9 - 5x)(9 + 5x) = 81 - 25 {x}^{2} \\ 6)(2y - 0.3)(2y + 0.3) = 4 {y}^{2} - 0.09$

$7)(6k - 1)(6k + 1) = 36 {k}^{2} - 1 \\ 8)(b - \frac{2}{3})(b + \frac{2}{3} ) = {b}^{2} - \frac{4}{9}$

$9)(11x - y)(11x + y) = 121 {x}^{2} - {y}^{2}$

$1) {x}^{2} + 2xy + {y}^{2} = {(x + y)}^{2} \\ 2)4 {x}^{2} + 4x + 1 = {(2x + 1)}^{2} \\ 3)36 - 12a + {a}^{2} = {(6 - a)}^{2} \\ 4)1 - 2a + {a}^{2} = {(1 - a)}^{2}$

$5) \frac{1}{4} + {x}^{2} - x = \frac{1}{4} (1 + 4 {x}^{2} - 4x) = \frac{1}{4} (1 - 4x + 4 {x}^{2} ) = \frac{1}{4}{ (1 - 2x)}^{2}$

$6) {a}^{2} - 2ab + {b}^{2} = {(a - b)}^{2} \\ 7) {c}^{2} + 10c + 25 = {(c + 5)}^{2} \\ 8) {p}^{2} + 36 - 12p = {p}^{2} - 12p + 36 = {(p - 6)}^{2}$

$9) \frac{9}{16} {a}^{2} - 2ab + \frac{16}{9} {b}^{2} = {( \frac{3}{4}a - \frac{4}{3} b) }^{2}$

$10)9 + {a}^{2} - 6a = {a}^{2} - 6a + 9 = {(a - 3)}^{2}$