Question

РЕШИТЬ ЧЕРЕЗ ДИСКРИМИНАНТ ♥️

Answer 1

$12x^2+7x+1\geq 0\\\\12x^2+7x+1=0\\\\D=b^2-4ac=7^2-4*12*1=49-48=1\\\\x_1=\frac{-b+\sqrt{D} }{2a}=\frac{-7+\sqrt{1} }{2*12}=\frac{-7+1}{24}=\frac{-6}{24}=-\frac{1}{4}=-0,25\\\\x_2=\frac{-b-\sqrt{D} }{2a}=\frac{-7-\sqrt{1} }{2*12}=\frac{-7-1}{24}=\frac{-8}{24}=-\frac{1}{3}$

x ∈ ( -∞ ; - $\frac{1}{3}$ ]  ∪ [ - $\frac{1}{4}$ ; +∞ )