Предмет: Алгебра, автор: m106915

Швидкість одного поїзда на 10 км/год більша за швидкість другого, тому 400км він приїжджає на 2год швидше, ніж другий поїзд. Знайдіть швидкість другого поїзда.

Ответы

Автор ответа: Пеппер

Ответ:

40 км/год

Объяснение:

Нехай швидкість другого поїзда х км/год, тоді швидкість першого поїзда х+10 км/год. Маємо рівняння:

400/х - 400/(х+10) = 2

400х+4000-400х=2х²+20х

х²+10х-2000=0

За теоремою Вієта х=-50 (не підходить) х=40

Швидкість другого поїзда 40 км/год

m106915: Очень большое спасибо

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