Предмет: Алгебра, автор: gerasenkovika990

sin2x -3sinx-4=0 розвязати тригонометричне рівнняння

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Автор ответа: Аноним

1

Ответ:

$\sin(2x) - 3 \sin(x) - 4 = 0 \\ 2x - 3x - 4 = 0 \\ - x - 4 = 0 \\ - x = 4 \\ x = - 4$

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