Предмет: Алгебра, автор: ivannaaa7

розв'яжіть рівняння 6x2+х-7=0​

Ответы

Автор ответа: dddddkoll3
2

6x^{2}+x-7=0\\D=1-4*6*(-7)=1+168=169\\x1=\frac{-1+\sqrt{169} }{2*6} =\frac{12}{12} =1\\x2=\frac{-1-\sqrt{169}}{2*6}=\frac{-14}{12}=-\frac{7}{6} =-1\frac{1}{6}

Автор ответа: Lillasy
0

Відповідь:

12X+ Х -7=0

13Х-7=0

13Х=7

Х=7/13

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