Question

Сократите дробь срочно

Answer 1

$\frac{a^{2} +b^{2}+2ab-9 }{a^{2}+ab-3a }=\frac{(a^{2} +2ab+^{2} )-3^{2}}{a(a+b-3)} =\frac{(a+b)^{2}-3^{2}}{a(a+b-3)}=\frac{(a+b-3)(a+b+3)}{a(a+b-3)}=\boxed{\frac{a+b+3}{a}}$