Question

решите выражение (n+6)²+(2-n) при n =
$- \frac {5}{12}$
​

Answer 1

$n = \frac{ - 5}{12}$

$(n + 6) {}^{2} + 2 - n = {n}^{2} + 12n + 36 + 2 - n$

$n {}^{2} + 11n + 38$

$( \frac{ - 5}{12} ) {}^{2} + 11 \times \frac{ - 5}{12} + 38$

$\frac{25}{144} - \frac{55}{12} + 38$

$\frac{25 - 660 + 5472}{144} = \frac{4837}{144} = 33 \times \frac{85}{144}$