Question

$frac{1}{x(x+1)}+ frac{1}{(x+1)(x+2)}- frac{1}{4}=0$

Answer 1

(x+2+x)/x(x+1)(x+2)-1/4=0
2(x+1)/x(x+1)(x+2)-1/4=0
2/x(x+2)-1/4=0
8-x^2-2x=0
x^2+2x-8=0
x=-1+-3
x=-4
x2=2

Answer 2

Большое спасибо!