Question

СРОЧНО.......,...............​1(

Answer 1

Ответ:

$\lim\limits _{x \to 1}\Big(\dfrac{1}{x-1}-\dfrac{3}{1-x^3}\Big)=[\ \infty -\infty \ ]=\lim\limits _{x \to 1}\Big(\dfrac{1}{x-1}-\dfrac{3}{(1-x)(1+x+x^2)}\Big)=\\\\\\=\lim\limits _{x \to 1}\dfrac{-(1+x+x^2)-3}{(1-x)(1+x+x^2)}=\lim\limits _{x \to 1}\dfrac{-(x^2+x+4)}{(1-x)(1+x+x^2)}=\Big[\ \dfrac{-6}{0}\ \Big]=\infty$