Question

-3*(6y-2)+5*(3y+1)=20​

Answer 1

Ответ:

-18y+6+15y+5=20

-3y+11=20

x=-3

Answer 2

$-3*(6y-2)+5*(3y+1)=20\\-18y + 6 + 15y + 5 = 20\\-3y + 11 = 20\\-3y = 20 - 11 = 9\\y = -\frac{9}{3} = -3$

Ответ: -3.