Question

СРОЧНО НУЖНО РЕШИТЬ!!!!!!!!!!!

Answer 1

Ответ:

Объяснение:

решено

Answer 2

Ответ:

a)

$f'(x) = 4 {(x - 3)}^{3} \times (x - 3) '= 4 {(x - 3)}^{3}$

б)

$f'(x) = 2(2x + 1) \times (2x + 1)' = (4x + 2) \times 2 = \\ = 8x + 4$

в)

$f'(x) = 3 {(3 - 4x)}^{2} \times (3 - 4x) '= \\ = 3 {(3 - 4x)}^{2} \times ( - 4) = - 12 {(3 - 4x)}^{2}$

г)

$f'(x) = ( {( {x}^{2} - 3) }^{ \frac{1}{2} } ) ' = \frac{1}{2} {( {x}^{2} - 3) }^{ - \frac{1}{2} } \times ( {x}^{2} - 3) '= \\ = \frac{1}{2 \sqrt{ {x}^{2} - 3 } } \times 2x = \frac{x}{ \sqrt{ {x}^{2} - 3} }$

д)

$f'(x) = 2 {(2x \cos(0) + {x}^{2} )}^{2} \times (2x \cos(0) + {x}^{2} )' = \\ = 2(2x + {x}^{2} ) {}^{2} \times (2 + 2x) = \\ = (4 + 4x) {(2 {x}^{2} + {x}^{2}) }^{2}$

е)

$f'(x) = - \frac{1}{3} ( - \sin(3x + \frac{\pi}{4} ) ) \times (3x + \frac{\pi}{4} ) '= \\ = \frac{1}{3} \sin(3x + \frac{\pi}{4}) \times 3 = \sin(3x + \frac{\pi}{4} )$