Question

cos(23п/4)-sin(16п/4)-ctg|-11п/2|

Answer 1

cos(23π/4) - sin(16π/4) - ctg|-11π/2| = cos(6π - π/4) - sin(4π) - ctg|6π - π/2| =
= cos(π/4) - 0 - ctg(6π - π/2) = √(2)/2 + ctg(π/2) = √(2)/2 + 0 = √(2)/2
Ответ: √(2)/2
Прямые скобки приняты как знак модуля или |-11π/2| = |11π/2| = 11π/2 = 6π - π/2

Answer 2

спасибо большое)))