Предмет: Литература, автор: Kalashy

Яка маса натрия сульфату міститься в розчині масою 43 г з масовою частки речовини 125%​

Ответы

Автор ответа: pavloyatsun95
1

Розв'язання:

Масу натрія сульфату знаходимо за формулою :

m(натрія сульфату) = m(розчину) × w(натрія сульфату) = 43 г × 125% = 53,75г

Відповідь: у 43г розчину міститься 53,75г натрія сульфату

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