Question

Найти производную.
Очеень срочно!!!!!!!$1)y=\frac{1}{3x+5} \\2)y=2x3stepeni-4\sqrt{16} +cos 2x \\3)y=(2x-7)7stepeni\\4)y= -2sin \frac{x}{3} +\frac{x}{5}$

Answer 1

Ответ:

1

$y = \frac{1}{3x + 5} = {(3x + 5)}^{ - 1}$

$y' = - {(3x + 5)}^{ - 2} \times ( 3x + 5) '= \\ = - \frac{3}{ {(3x + 5)}^{2} }$

2

$y = 2 {x}^{3} - 4 \sqrt{16} + \cos(2x)$

$y' = 2 \times3 {x}^{2} - 0 - \sin(2x) \times (2x) = \\ = 6 {x}^{2} - 2 \sin(2x)$

3

$y = {(2x - 7)}^{7}$

$y' = 7 {(2x - 7)}^{6} \times (2x - 7)' = \\ = 7 {(2x - 7)}^{6} \times 2 = 14 {(2x - 7)}^{6}$

4

$y = - 2 \sin( \frac{x}{3} ) + \frac{x}{5}$

$y' = \ - 2 \cos( \frac{x}{3} ) \times ( \frac{x}{3} ) '+ \frac{1}{5} = \\ = - \frac{2}{3} \cos( \frac{x}{3} ) + \frac{1}{5}$