Question

алгебра помогите,хотя бы несколько помогите​

Answer 1

Ответ:

1

$y' = 2(4x -3 ) \times (4x - 3) '= \\ = 2(4x - 3) \times 4 = 8(4x - 3) = \\ = 12x - 24$

2

$y' = 7 {(3 {x}^{4} + 8x) }^{6} \times (3 {x}^{4} + 8x) '= \\ = 7(12 {x}^{3} + 8) {(3 {x}^{4} + 8x)}^{6}$

3

$y '= \frac{1}{2} {(3x - 14)}^{ - \frac{1}{2} } \times (3x - 14) '= \\ \frac{3}{2 \sqrt{3x - 14} }$

4

$y' = \frac{1}{2} {(2 {x}^{3} + 4x)}^{ - \frac{1}{2} } \times (2 {x}^{3} + 4x)' = \\ = \frac{6 {x}^{2} + 4 }{2 \sqrt{2 {x}^{3} + 4x } } = \frac{3 {x}^{2} + 2 }{ \sqrt{2 {x}^{3} + 4x} }$

5

$y '= - \frac{1}{ \sin {}^{2} (3x + \frac{\pi}{6} ) } \times (3x + \frac{\pi}{6} )' = \\ = - \frac{3}{ \sin {}^{2} (3x + \frac{\pi}{6} ) }$

6

$y' = \cos( \frac{x}{4} ) \times ( \frac{x}{4} )' = \frac{1}{4} \cos( \frac{x}{4} )$