Предмет: Геометрия, автор: tutsik

в ромбе АВСД проведина высота ВК,которая делит сторону АД на отрезке АК=9 см и КД=9 см .найти углы ромба

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Автор ответа: volodyk

ромб АВСД, ВК-высота, АК=9, КД=99, АД=АК+КД=9+9=18=АВ=ВС=СД треугольник АВК прямоугольный, АК=1/2АВ, значит угол АВК=30, тогда уголА=90-30=60=уголС, уголВ=уголД=180-60=120

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