Question

алгебра помогите пожалуйста​

Answer 1

$1)\left \{ {{1,5x=1} \atop {-3x+2y=-2}} \right.\\\\\left \{ {{x=\frac{2}{3} } \atop {-3*\frac{2}{3}+2y=-2 }} \right.\\\\\left \{ {{x=\frac{2}{3} } \atop {-2+2y=-2}} \right.\\\\\left \{ {{x=\frac{2}{3} } \atop {2y=0}} \right.\\\\\left \{ {{x=\frac{2}{3} } \atop {y=0}} \right.\\\\Otvet:\boxed{(\frac{2}{3} \ ; \ 0)}$

Одно решение

$2)\left \{ {{2x=11-3y} \atop {6y=22-4x}} \right. \\\\\left \{ {{2x+3y=11} \atop {4x+6y=22}} \right.\\\\\frac{2}{4}=\frac{3}{6} =\frac{11}{22}$

Система имеет бесконечное множество решений

$3)\left \{ {{5x+y=4} \atop {x+y-6=0}} \right. \\\\-\left \{ {{5x+y=4} \atop {x+y=6}} \right. \\------\\4x=-2\\\\x=-0,5\\\\y=6-x=6-(-0,5)=6,5\\\\Otvet:\boxed{(-0,5 \ ; \ 6,5)}$

Одно решение

$4)\left \{ {{4y-x=12} \atop {3y+x=-3}} \right.\\\\-\left \{ {{x-4y=-12} \atop {x+3y=-3}} \right. \\-------\\-7y=-9\\\\y=1\frac{2}{7}\\\\x=-3y-3=-3*\frac{9}{7}-3=-3\frac{6}{7}-3=-6\frac{6}{7}\\\\Otvet:\boxed{(-6\frac{6}{7} \ ; \ 1\frac{2}{7})}$

Одно решение