Question

x^2-4x-12=0
Перший корінь 6
Другий корінь ?

Answer 1

Ответ:

$x {}^{2} - 4x - 12 = 0 \\ d = 16 - 4 \times 1 \times ( - 12) \\ d = 16 + 48 \\ \sqrt{d} = \sqrt{64} = 8 \\ x1 = \frac{4 + 8}{2} = \frac{12}{2} = 6 \\ x2 = \frac{4 - 8}{2} = - \frac{4}{2} = - 2$

Answer 2

$x^{2}-4x-12=0\\\\x_{1}=6\\\\x_{1}*x_{2} }=-12\\\\x_{2}=-12:x_{1}=-12:6=-2\\\\\boxed{x_{2}=-2}$