Question

Помогите 7 задание, ОЧЕНЬ ПРОШУ, срочно надо, пожалуйста(((

Answer 1

Ответ:

Объяснение:

$\displaystyle\\\left \{ {{a_1^2+a_3^2=58} \atop {a_2+a_4=14}} \right. \\\\\\\left \{ {{a_1^2+(a_1+2d)^2=58} \atop {a_1+d+a_1+3d=14}} \right. \\\\\\\left \{ {{a_1^2+(a_1+2d)^2=58} \atop {2a_1=14-4d}} \right. \\\\\\\left \{ {{(7-2d)^2+(7-2d+2d)^2=58} \atop {a_1=7-2d}} \right. \\\\\\\left \{ {{49-28d+4d^2+49-58=0} \atop {a_1=7-2d}} \right.\\\\\\\\\left \{ {{4d^2-28d+40=0} \atop {a_1=7-2d}} \right.\\\\\\ \left \{ {{d^2-7d+10=0} \atop {a_1=7-2d}} \right.$

по Виета

1)  d=5;   a₁=7-2*5= - 3 ;a₂ = -3 + 5 = 2; a₃ = 2 + 5 = 7; a₄ = 7 + 5 = 12

прогрессия  -3; 2; 7; 12

или

2) d=2;   a₁ = 7 - 4 = 3 ;a₂ = 3 + 2 = 5; a₃ = 5 + 2 = 7; a₄ = 7 + 2 = 9

прогрессия   3; 5; 7; 9

О т в е т: -3; 2; 7; 12    или     3; 5; 7; 9