Question

для функции f(x)=3sin^x вычислите f'(-п/4).

Answer 1

f'(х)=3cosx.

f'(-π/4)=3cosx=3cos (-π/4)=3(-√2/2)=-3√2/2

Answer 2

f'(х) = 3 cosx
f''(х) = - 3 sinx
f''(-π/4) = - 3 sin(-π/4) = -3 * (-√2)/2 = 1,5√2