Question

помагите пж даю 35 баллов

Answer 1

воттттттттт)))))))))

Answer 2

$1)(\frac{1}{2})^{-2} *(\frac{1}{2})^{3}=(\frac{1}{2})^{-2+3} =\frac{1}{2}\\\\2)2^{-3}*2^{7} =2^{-3+7}=2^{4}=16\\\\3)3^{-7}*3^{6}=3^{-7+6}=3^{-1}=\frac{1}{3}\\\\4)(\frac{1}{7})^{3}*(\frac{1}{7})^{-4}=(\frac{1}{7})^{3-4} =(\frac{1}{7})^{-1}=7\\\\5)6^{5}*6^{-3}=6^{5-3}=6^{2}=36\\\\6)5^{-4}:5^{-6}=5^{-4-(-6)}=5^{-4+6}=5^{2}=25 \\\\7)5^{-3}:5^{-6}=5^{-3-(-6)}=5^{-3+6}=5^{3}=125$

$8)(\frac{1}{7})^{-3}:(\frac{1}{7})^{-5}=(\frac{1}{7})^{-3-(-5)}=(\frac{1}{7})^{-3+5}=(\frac{1}{7})^{2}=\frac{1}{49} \\\\9)(\frac{1}{2})^{3} *(\frac{1}{2})^{-8}=(\frac{1}{2})^{3-8}=(\frac{1}{2})^{-5}=2^{5}=32\\\\10)(\frac{1}{2})^{-4} :(\frac{1}{2})^{-9}=(\frac{1}{2})^{-4-(-9)}=(\frac{1}{2})^{-4+9}=(\frac{1}{2})^{5}=\frac{1}{32}$