Question

1034. 1) 3x + (5 x - 2) <3 - 2x,
4(5x - 1) - 21x > 1 - 3x;
2) 17 - 11x < 9x - 2(5x + 7),
6- X > 2(1 - 4x) - 3(1 - 3x).​

Answer 1

Ответ:

{

4(5x−1)−21x≥1−3x

3x+(5x−2)≤3−2x

{

20x−4−21x≥1−3x

8x−2≤3−2x

{

2x≥5

10x≤5

{

x≥2.5

x≤0.5

очевидно, что нет решений.

\left \{ {{7-11x \textless 9x -2(5x+7)} \atop {6-x \textgreater 2(1-4x) - 3(1-3x)}} \right. \left \{ {{7-11x \textless 9x -10x -14} \atop {6-x \textgreater2 - 8x - 3+9x)}} \right. \left \{ {{21 \textless 10x} \atop {7 \textgreater 2x)}} \right. \left \{ {{2.1 \textless x} \atop {3.5\textgreater x)}} \right. \Leftrightarrow x \in (2.1; 3.5){

6−x\textgreater2(1−4x)−3(1−3x)

7−11x\textless9x−2(5x+7)

{

6−x\textgreater2−8x−3+9x)

7−11x\textless9x−10x−14

{

7\textgreater2x)

21\textless10x

{

3.5\textgreaterx)

2.1\textlessx

⇔x∈(2.1;3.5)