Предмет: Физика, автор: krainkrainov97

Сила тока в цепи гальванического элемента с ЭДС 12В равна 2А. Падение напряжения на внешней части цепи 6В. Определить сопротивление внешней части цепи и внутреннее сопротивление. Определить потребляемую мощность.

Ответы

Автор ответа: DedStar

Ответ:

Объяснение:

Дано:

ЭДС = 12 В

I = 2 А

U = 6 В

__________

R - ?

r - ?

P - ?

Сопротивление внешней цепи:

R = U / I = 6 / 2 = 3 Ом

Падение напряжения на внутреннем сопротивлении гальванического элемента:

Ur = ЭДС - U = 12 - 6 = 6 В

Внутреннее сопротивление:

r = Ur / I = 6 / 2 = 3 Ом

Мощность:

P = U·I = 6·2 = 12 Вт

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